The probability of an LCD being defective is 0.1, which means the probability of an LCD not being defective is 1 - 0.1 = 0.9.
Since the LCDs being defective are independent events, the probability of all 5 LCDs not being defective is the product of the probabilities of each LCD not being defective:
P(not defective, not defective, not defective, not defective, not defective) = 0.9 * 0.9 * 0.9 * 0.9 * 0.9
= (0.9) ^ 5
= 0.59049
So, the probability that all 5 LCDs are not defective is approximately 0.59049.
A manufacturer of liquid crystal displays (LCDs) is studying their production lines. The probability of sampling a defective LCD is 0.1. A sample of 5 LCDs is taken. You may assume that an LCD being defective is independent of any of the others being defective.
What is the probability that all 5 LCDs are NOT defective?
1 answer