Asked by Schaun
                A manufacturer of a product has a monthly cost for producing x items given by C(x) = 10+2x. The selling price function for this product is p(x) = 50-.01x. Find the maximum profit the company can expect monthly
            
            
        Answers
                    Answered by
            Steve
            
    the revenue function is price * quantity, so
R(x) = x(50-.01x)
profit is revenue less cost, so
P(x) = R(x)-C(x)
= x(50-.01x) - (10+2x)
= -0.01x^2 + 48x - 10
Now just set dP/dx=0 and evaluate P there.
Or, just use your Algebra I skills and find the vertex of the parabola.
    
R(x) = x(50-.01x)
profit is revenue less cost, so
P(x) = R(x)-C(x)
= x(50-.01x) - (10+2x)
= -0.01x^2 + 48x - 10
Now just set dP/dx=0 and evaluate P there.
Or, just use your Algebra I skills and find the vertex of the parabola.
                    Answered by
            Damon
            
    profit = p(x) - C(x)
= 50-.01 x - 10 - 2x
= 40-2.01 x
max at x = 0
I bet you have a typo though.
    
= 50-.01 x - 10 - 2x
= 40-2.01 x
max at x = 0
I bet you have a typo though.
                    Answered by
            Damon
            
    Oh, go with what Steve said.
    
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