A man's gold wedding ring has an inner diameter of 2.0cm at 30∘C.
Part A
If the ring is dropped into boiling water, what will be the change in the inner diameter of the ring?
1 answer
ΔL =L αΔT =2 •10⁻²•14•10⁻⁶•70=1.96•10⁻⁵m=1.96•10⁻² mm