A man's age is 4 times the combined age of a two sons. One of whom is 3 times as old as the other. In 24 years their combined ages will be 12 year less than their father's age . Find their respective age ????

Question

A man's age is 4 times the combined age of a two sons. One of whom is 3 times as old as the other. In 24 years their combined ages  will be 12 year less than their father's age . Find their respective age ????

Henry · Answer

X Yrs old = Age of one son.
3x yrs old = Age of other son.
4(x+3x) = 16x = Age of the father.

(x+24) + (3x+24) = (16x+24) - 12.
4x + 48 = 16x + 12
4x - 16x = 12 - 48
-12x = -36
X = 3

x+24 = 3+24 = 27 Yrs=Youngest son's age,
3x+24 = 9+24 = 33 Yrs=Oldest son's age.
16x+24 = 48+24=72 Yrs=The father's age.