A manager purchased a total of 21 coffee mugs and key chains. Each coffee mug cost $8.50, and each key chain cost $2.75.

If the manager spent a total of $132.50, how many coffee mugs did the manager purchase?

1 answer

Let \( x \) be the number of coffee mugs purchased, and \( y \) be the number of key chains purchased. We can set up the following equations based on the given information:

  1. The total number of items: \[ x + y = 21 \]

  2. The total cost of the items: \[ 8.5x + 2.75y = 132.5 \]

We can solve this system of equations starting with the first equation. We can express \( y \) in terms of \( x \): \[ y = 21 - x \]

Now, substitute \( y \) into the second equation: \[ 8.5x + 2.75(21 - x) = 132.5 \]

Expanding the equation: \[ 8.5x + 57.75 - 2.75x = 132.5 \]

Combining like terms: \[ (8.5 - 2.75)x + 57.75 = 132.5 \] \[ 5.75x + 57.75 = 132.5 \]

Now, isolate \( x \): \[ 5.75x = 132.5 - 57.75 \] \[ 5.75x = 74.75 \] \[ x = \frac{74.75}{5.75} \] \[ x = 13 \]

Now that we have \( x \), we can find \( y \): \[ y = 21 - x = 21 - 13 = 8 \]

Thus, the manager purchased \( \boxed{13} \) coffee mugs.

To verify, we calculate the total cost with these values:

  • Cost of coffee mugs: \( 13 \times 8.5 = 110.5 \)
  • Cost of key chains: \( 8 \times 2.75 = 22 \)

Adding these: \[ 110.5 + 22 = 132.5 \]

Since the total cost matches, the solution is confirmed. The manager purchased \( \boxed{13} \) coffee mugs.