A man with normal color vision marries a woman who is colorblind. What percentage of their sons would be colorblind, what percentage of their daughters would be colorblind, what percentage of their daughters would be carriers of the colorblind gene?

Answer 1

to be color blind, all X genes must have the trait. A male has only one X gene, females two X.

So the mom is XcXc, and she passes one of these Xc to each daughter and son. So the sons will be colorblind...they got it from mom. The daughers will get mom's Xc, and dad's Xo, making them carriers, but not colorblind.

Man: XoY
Mom: XcXc
daughters: XcXo
sons: XcY