A man who is standing on the roof of a building throws a baseball vertically downward toward the sidewalk at a speed of 6.85m/s. The sidewalk is 34.9m below the roof. Calculate the speed of the ball just as it hits the pavement.

Answer 1

finalenergy=initial PE+intialKE
1/2 m v^2=mg*34.9+1/2 m 6.85^2
or v= sqrt (2*9.8*34.9+6.85^2)