A man walks five miles due east and then three miles in a direction 60° north of east .calculate the displacement of the man.

Answer 1

I made a sketch and got triangle ABC, with angle B = 120°, AB = 5, and BC = 3

looks like a normal cosine law problem
AC^2 = 5^2 + 3^2 - 2(5)(3)cos120°
....

then use the sine law to find angle A