A man walks 5 m at 37 degree north of east then 10 m at 60 degree west of north.?

calculate the magnitude and direction of his displacement.

5 answers

D = 5m[37o] + 10m[150o]

X = 5*Cos37 + 10*Cos150 = -4.67 m.
Y = 5*sin37 + 10*sin150 = 8.00 m.

Tan Ar = Y/X = 8/-4.67 = -1.71501
Ar = -59.75o = Reference angle.
A = -59.75 + 180 = 120.25o = Direction.

D=Y/sin A = 8.00/sin120.25=9.26m[120.25]
= Magnitude and direction.

how to get 10m[150o] ??? explain please

Ei dguitdhuihfr

90+60 = 150o CCW from +x-axis.

The diagram to follow

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