A man walks 3m north then 4m east.calculate his displacement from the starting point.

Answer 1

distance = sqrt (3^2 + 4^2) = 5

sin angle north of east = 3/5 = 0.6

Answer 2

sqrt (3^2 + 4^2) ...pls break this down, don't understand how its equal to 5. Thanks

Answer 3

square root (3^2 + 4^2) = 9 + 16 = 25 square root of 25 equals 5

ur welcome :)

Answer 4

28+$_+88-3+=ryh36+++