A man swim at a speed of 50m/min, swims 100m against the current and 100m with the current. if the time difference between the two times is 3min 45sec. find the speed of the current?

Answer 1

since time = distance/speed,

100/(50-x) = 100/(50+x) + 3.75

Now just find x.

Answer 2

In general, distance = rate x time
This case:
distance = (rate + current) x time

distance = (rate - current) x time

100 = (50 -c)(t)
100 = (50+c) (t + 3 3/4 minutes)

This should get you started.

Answer 3

You got your speeds reversed, John.

The slower speed takes longer.