his distance, after t seconds, is
s(t) = 15t + t^2
The 5th second is the time between the end of the 4th second and the end of the 5th second. So, the distance covered is
s(5)-s(4) = (15*5+5^2) - (15*4+4^2) = 100-76 = 24m
The distance covered in the first 10 seconds is thus
s(10)-s(0) = s(10) = 250m
A man starts with a velocity of 15m/s and moves with an acceleration of 2m/s^2.what distance does he cover in the fifth second? What distance does he cover in 10s
1 answer