A man standing 2040m from the foot of a high building claps his hands and hears the echo. 4 second later (speed of sound in air at 0 ^ 0 * c is 331m / s )

Question

a. What is the velocity of the sound in the air?
b. What is the temperature at that place?

Answer 1

a. We can use the formula:

distance = speed x time

The man claps his hands and hears the echo 4 seconds later. This means the sound had to travel a total of 4080 meters (2040m to the building and then back to the man). So:

4080m = speed x 4s

Speed = 1020 m/s

Therefore, the velocity of the sound in the air is 1020 m/s.

b. The speed of sound in air depends on the temperature of the air. At 0 ^ 0 *C, the speed of sound in air is 331 m/s. We can use the formula:

speed = 331 m/s x sqrt(1 + (T/273))

where T is the temperature in degrees Celsius.

We can rearrange this formula to solve for T:

T = (speed/331)^2 x 273 - 273

Plugging in the speed we found above, we get:

T = ((1020 m/s)/331)^2 x 273 - 273

T ≈ 39°C

Therefore, the temperature at that place is approximately 39°C.