A man spends 1/5 of his income on food and 1/3 of the remainder on his car.If he then has 286.00 left what is his income

Answer 1

i - (i / 5) - (4 i / 15) = 286

15 i - 3 i - 4 i = 286 * 15

Answer 2

1-1/5 = 5/5-1/5 = 4/5 remainder.
4/5-1/3 = 12/15-5/15 = 7/15 remains.

7x/15 = 286
X =

Answer 3

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Answer 4

I dont understand

Answer 5

1-1/5 for food = 4/5 left
1/3 of 4/5 on the car = 4/15
1/5 for food + 4/15 on the car = 7/15 spent
For the value of what is left
1-7/15 of the total amount = 286
8/15 of x = 286
X = 286*15/8
X = 536.25

Answer 6

To break it down step by step:

Let's call the man's income "x".

1. He spends 1/5 of his income on food, so he has 4/5 of his income remaining.
2. Of that remaining amount, he spends 1/3 on his car. 1/3 of 4/5 is (1/3) x (4/5) = 4/15.
3. He has now spent 1/5 on food and 4/15 on his car, which adds up to 1/5 + 4/15 = 7/15 of his income.
4. We are told that he has 286 left from the remaining amount after spending on food and car.
5. So the equation becomes: (8/15)x = 286 (since he has 8/15 of his income remaining)
6. Solving for x, we get x = 286 x (15/8) = 536.25.

Therefore, the man's income is $536.25.