a. d1 = 0.5a*t^2 = 0.25*8^2 = 16 m.
V1 = at = 0.5 * 8=4 m/s=Max. velocity.
a = (V-V1)/t = (0-4) / 1.5=-2.67m/s^2.
d2 = (V^2-V1^2)/2a.
d2=(0-16) / -5.33=3 m.=Sliding distance.
Dt = d1 + d2 = 16 + 3 = 19 m. = Total
dist. traveled.
a man run, accelerating at 0.5 m/s^2, for 8 sec. He then slides to a stop in 1.5 sec.
a.) What total distance did he travel?
b.) what was his average velocity?
2 answers
b. Vavg = Dt/T = 19 / (8+1.5) = 2m/s.