friction force=100, constant speed
120-100=ma
solve for a
a man pushes a packing case which has a total mass of 50 kg across a floor at a constant speed of 0.4 m s-1 by exerting a horizontal force of 100 N.
(a) what was the resultant force on the case?
> F = ma
F = 50 * 0
F =0
(b) what was the frictional force acting on the case?
> 0 (frictional force is the same as resultant force?)
(c) if the force exerted by the man is increased to 120 N, what will the acceleration be?
> F = ma
120 = 50 * a
a = 120 / 50
a = 2.4 m s-2
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