A man pulls a 300N object across a horizontal surface using a 100 N force applied at a 35 degree angle. What is the normal force? If the object is pulled at constant speed, what is the coefficient of friction?

Answer 1

weight minus vertical pulling component
... Fn = 300 - 100 sin(35º)

horizontal pulling component divided by normal force
... [100 cos(35º)] / Fn

Answer 2

200