a. work=force*distance=53cos18*122
b. at constant speed, up the incline, he goes h distance upward, or 122sin6.7 high
work done=mgh=10*g*122sin6.7
A man pulls a 10 kg box across a smooth floor with a force of 53 newtons at an angle of 18 degrees and for a distance of 122 meters. How much work, to the nearest joule, does he do?If the floor is angled upward at 6.7 degrees and the man pulls the box up the floor at constant speed what is the work he does to the nearest joule
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