Sum moments about the right end.
Tl*3-23.9g*1.5-76.1g(d)=0 where d is where the man is standing.
1/6 length scaffold is .5m, so the man is standing at 1.5-.5=1.0 or d=1.0 check that.
solve for tension left Tl
A man of mass 76.1kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 23.9kg and is 3.0m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope?
b).what is the tension in the left rope?
2 answers
A uniform rod of length 10m and mass 50kg is suspended from two verticle ropes attached to its ends.
a) A woman of mass 70kg stands at the middle of the rod. What is the tension in each rope?
b) The ropes break if the tension in them exceeds 750N. how far to the right can the woman walk before the rope breaks?
a) A woman of mass 70kg stands at the middle of the rod. What is the tension in each rope?
b) The ropes break if the tension in them exceeds 750N. how far to the right can the woman walk before the rope breaks?