The sex ratio would still be the same, 50% of each. However, if you are looking for those who would survive, use a Punnett square.
https://www.google.com/search?client=safari&rls=en&q=punnett+square&ie=UTF-8&oe=UTF-8&gws_rd=ssl
With x standing for the recessive lethal gene, mom would be Xx and dad would be XY. Assume chance variation.
A man marries a woman who is heterozygous for a recessive X-linked lethal gene "X" expressed in very early development. If the couple had many normal children, what would be the predicted sex ratio among their children?
I'm so confused. If it's a lethal allele, how would do you predict this?
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