A man left half of his money to his first son and 3/8 to his second son and the rest #80000 to his third son. How much did he leave to his second son

Answer 1

Let's assume that the man had $x as his total money.

He left half of his money to his first son: (1/2)x.
He left 3/8 of his money to his second son: (3/8)x.

The rest of his money, which is $80000, he left to his third son.

So, the equation becomes:
(1/2)x + (3/8)x + $80000 = x.

Combining like terms on the left side:
(4/8)x + (3/8)x + $80000 = x.
(7/8)x + $80000 = x.

Subtracting (7/8)x from both sides:
$80000 = (1/8)x.

Multiplying both sides by 8 to solve for x:
$80000 * 8 = x.
$640000 = x.

Therefore, the man left 3/8 of his money, which is (3/8)*$640000 = $<<3/8*640000=240000>>240000 to his second son. Answer: \boxed{240000}.