Let x be the amount of money the man had initially.
He left x/2 to his first son.
He left 3/8*x to his second son.
He left x/2 + 3/8*x + #80000 = x(1/2 + 3/8) + #80000 = x(4/8 + 3/8) + #80000 = x(7/8) + #80000 = (7/8)x + #80000 to his third son.
So the man left (7/8)x + #80000 = (3/8)x to his second son.
In other words, (3/8)x = (7/8)x + #80000.
Let's solve for x.
(3/8)x - (7/8)x = #80000
(1/4)x = #80000
x = #80000 * 4 = #<<320000=320000>>320000.
So the man left (3/8)*320000 = #96000 to his second son. Answer: \boxed{#96000}.
A man left half of his money to his first son, 3/8 to his second son, and the rest, #80000 to his third son. How much did he leave to his second son?
1 answer