a man jumps off a bridge to see how high it is. he measures his time of descent. he is in the air for 3 seconds before splashing into the water below. how high is the bridge above the water?how fast is the man going as he hits the water?

Answer 1

use v=u+at to find final velocity

v=final velocity
u=initial velocity = 0 m s^-1
a=acceleration due to gravity=9.8 m s^-2
t=time taken = 3 s

use s=ut + 0.5at^2 to find height

where s= distance travelled