The second man is travelling for 2 seconds.
The first man is travelling for 3 seconds.
acceleration due to gravity = 9.8m/sec^2
d = vt
v = at
we can combine to get
d =at^2 a in this case is g.
You can find the distance of each jumper and find the difference.
A man jumps from a great height and falls freely to the Earth. Another man jumps from the same height 1 s later. How much are the two men separated by, 2 s after the second man jumps?
I'm not sure exactly how to tackle this question. I'm sure I'm making it more complicated than it is supposed to be.
Thanks.
3 answers
Great. Thanks a lot.
You are welcome.