time of flight: 25m/54m/s=25/54 s
distance fell: h=1/2 g t^2
A man is using a bow and arrow for the first time of his life. He is 25 meters from the target and aims directly at the center of the target. Surprisingly the arrow leaves the bow with a velocity of 54 m/s directly towards the center of the target and initially the velocity is parallel to the floor. How far below the center does the arrow hit the target?
2 answers
The arrow takes
t = (25 m)/(54 m/s) = 0.46296 s
to get to the target.
Calculate how far it falls in that time using
y = (g/2)*t^2
g is the acceleration of gravity. You must know its value by now.
t = (25 m)/(54 m/s) = 0.46296 s
to get to the target.
Calculate how far it falls in that time using
y = (g/2)*t^2
g is the acceleration of gravity. You must know its value by now.
1 answer