A man has 3 pennies, 2 nickles, and 3 dimes. If he draws 1 coin randomly then replaces it and selects again randomly. What is the probability of getting less than 10 cents if his 1st draw was a penny?

Answer 1

So he already has 1 penny, which means he can only draw another penny or another nickel

Prob(as stated) = 3/8 + 2/8
= 5/8

Answer 2

Probability