A man flies a kite with a 100ft string. The angle of elavation of the string is 52*. how high of the ground is the kite.

Answer 1

To solve this problem, we can use trigonometry.

We know that the angle of elevation of the string is 52 degrees. Let's call the height of the kite from the ground as h.

Using trigonometry, the relationship between the height of the kite, the length of the string, and the angle of elevation is given by the equation:

tan(angle of elevation) = height / length of string

Substituting the given values:

tan(52°) = h / 100ft

Rearranging the equation to solve for h:

h = tan(52°) * 100ft

Using a calculator or trigonometric table, we find:

h ≈ 92.81ft

Therefore, the kite is approximately 92.81 feet high from the ground.