A man drop a stone of mass 2kg room the top of a building of height 15m when it reaches the ground find its kinetic energy.
3 answers
KE=initial PE=2*9.8*15 joules
K.E=initial P. E
:K.E=mgh
K.E=2*15*9.8
K.E=294
:K.E=mgh
K.E=2*15*9.8
K.E=294
According to law of conservation of energy potential energy of an object at the height is transfer is kinetic energy increases the ground
m=2kg
h=15m
g=10m/s
Kinetic energy=mgh
=2×10×15
=300J
m=2kg
h=15m
g=10m/s
Kinetic energy=mgh
=2×10×15
=300J