A man cycled from the market to his house at an average speeds of 6kmph. If he left the market at 4pm and reached hos house at 5:15pm how far is his house from the market

1 answer

The journey took 1 hour and 15 minutes (5:15pm - 4:00pm = 1 hour, 15 minutes).
Since he cycled at an average speed of 6 km/h, the distance he traveled can be calculated using the formula: distance = speed x time.
Converting 1 hour and 15 minutes to hours, we get 1.25 hours.
Therefore, the distance is: 6 km/h x 1.25 hours = 7.5 km.
Hence, his house is 7.5 kilometers away from the market.