A man cycled from the market to his house at an average speed of 6km p.h. If he left the market at 4.00p.m and reached his house at 5.15pm, how far is his house from the market?

1 answer

The man cycled for a total of 1 hour and 15 minutes, or 1.25 hours (5:15 PM - 4:00 PM = 1 hour and 15 minutes or 1.25 hours).

Since his average speed is 6 km/h, the distance he traveled can be calculated using the formula: distance = speed × time.

distance = 6 km/h × 1.25 hours = <<6*1.25=7.5>>7.5 km.

Therefore, his house is 7.5 kilometers away from the market.