A man claims he can safely hold on to a 9.7-kg child in a head-on collision with a relative speed of 112-mi/h lasting for 0.12 s as long as he has his seat belt on.
(a) Find the magnitude of the average force needed to hold onto the child. HELP
3 answers
The child is going from a speed of 112 mi/h to a speed of 0 in .12 seconds...so their is a deceleration...Does this help?
112 m/h = 180 km/h = 50 m/s
The deceleration rate is
a = (50 m/s)/0.12s = 416 m/s^2
That's about 42 g's.
The force to hold the child required is F = m a, which is about 42 times the child's weight.
Do the calculation and answer in Newtons or pounds..
The deceleration rate is
a = (50 m/s)/0.12s = 416 m/s^2
That's about 42 g's.
The force to hold the child required is F = m a, which is about 42 times the child's weight.
Do the calculation and answer in Newtons or pounds..
N=m*v/t
0 answers