A man can throw a ball a maximum horizontal distance of 73.4 meters. the acceleration is 9.8 m/s^2. How far can he throw the same ball vertically upward at the same initial speed?

Answer 1

d = Vo^2*sin(2A)/g = 73.4 m.
A = 45o @ max hor. distance.
Vo^2*sin(90)/9.8 = 73.4.
Vo^2/9.8 = 73.4
Vo = 26.8m/s[45o].
Yo = 26.8*sin45 = 19m/s. = Ver. component.

Y^2 = Yo^2 + 2g*h.
0 = 19^2 - 19.6h. h = ?.