A man 40 mm from the foot of a pole observes the angle of elevation of the pole to be 3 degrees.calculate the height of the pole

Answer 1

To solve this problem, we can use trigonometry. Let's assume the height of the pole is h.

We know that the tangent of the angle of elevation is equal to the opposite side (h) divided by the adjacent side (40 mm).

So, tan(3 degrees) = h/40 mm

We can rearrange this equation to solve for h:

h = 40 mm * tan(3 degrees)

Using a calculator, we find that tan(3 degrees) ≈ 0.0524.

h = 40 mm * 0.0524

h ≈ 2.096 mm

Therefore, the height of the pole is approximately 2.096 mm.

Answer 2

Given that triangle ABS is having <ABC=90 degrees, <BAC=30 degrees and /AB/= 22.6 cm. Find side /BC/

Answer 3

To find side BC, we can use the trigonometric ratio of sine.

We know that:

sin(30 degrees) = opposite side (BC) / hypotenuse (AB)

Rearranging the equation, we have:

BC = AB * sin(30 degrees)

Plugging in the values, we get:

BC = 22.6 cm * sin(30 degrees)

Using a calculator, we find that sin(30 degrees) ≈ 0.5.

BC = 22.6 cm * 0.5

BC = 11.3 cm

Therefore, the length of side BC is 11.3 cm.