A major-league pitcher can throw a baseball in excess of 41.3m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 15.2m away from the point of release?

Answer 1

t = time = distance/speed = 15.2/41.3

drop = (1/2)g t^2
= 4.9 t^2