V*t = 17 m.
t = 17/V = 17/37.8 = 0.1852 s.
d = 0.5g*t^2.
g = 9.8 m/s^2.
A major-league pitcher can throw a ball in excess of 37.8 m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 17.0 m away from the point of release?
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