speed = 92 mi/hr * 1 hr/3600 s * 621 m/mi
= 15.9 m/s
average speed = 15.9/2 = 7.9 m/s
time to stop = distance/speed = .15/7.9 = .0189 second
force * time = change of momentum
803 * .0189 = m (15.9 - 0)
m = .955 kg
A major-league catcher gloves a 92 mi/h pitch and brings it to rest in 0.15 m.
1-If the force exerted by the catcher is 803 N, what is the mass of the ball?
3 answers
speed = 92 mi/hr * 1 hr/3600 s * 1610 m/mi
= 41.1 m/s
average speed = 41.1/2 = 20.6 m/s
time to stop = distance/speed = .15/20.6 = .0073 second
force * time = change of momentum
803 * .0073 = m (41.1 - 0)
m = .142 kg
= 41.1 m/s
average speed = 41.1/2 = 20.6 m/s
time to stop = distance/speed = .15/20.6 = .0073 second
force * time = change of momentum
803 * .0073 = m (41.1 - 0)
m = .142 kg
A catcher stops 92 mi/h pitch in his glove bring it to rest in 0.15 m. If the force exerted by the catcher is 803N, what is the mass of the ball?