a) W = Fd = 145N * 4.6m = 667Nm
b) W = mgd cosθ = 20kg * 9.8m/s^2 * 4.6m * cos25° = 545.2Nm
c) W = Fd cosθ = 145N * 4.6m * cos25° = 471.3Nm
d) W = μFd = 0.3 * 145N * 4.6m = 261.5Nm
e) Total work done on suitcase = W = 667Nm + 545.2Nm + 471.3Nm + 261.5Nm = 2045Nm
f) Speed of suitcase = v = √(2W/m) = √(2 * 2045Nm/20kg) = 10.3m/s
A luggage handler pulls a 20kg suitcase up a ramp inclined at 25 degrees above the horizontal by a force F of magnigutde 145N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is .30. If the suitcase travels 4.6 m along the ramp calculate
a) work done on the suitcase by the force F
b)work done on suitcase by gravitational force.
c) work done on suitcase by normal force
d)work done on suitcase by friciton force
e)total work done on suitcase
f) If the speed of suitcase is zero at bottom of ramp what is its speed after it travels 4.6 m along the ramp?
Are these the correct equations I would use?
a)W=Fd
b)W=mgd cos theda
c)W=Fd cos theda
d) What would be the correct equation for part d)?
And could you help me on part e and f?
1 answer