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a long jumper jumps 10m and leaves the ground at an angle of 45 degrees.determine the speed he leaves the the ground at,

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The upward velocity is Vsin45. The horizontal veloicty is Vcos45

horizontal:
10m=Vcos45*t
time= 14.1/V

Vertical
Hfinal=hinitial+Vsin45*t- 4.9t^2
put what we found in for time, solve for v.

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