A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point

Question

A) 8.616 mi

B) 10 mi

C) 7.616 mi

D) 4.472 mi

I think it is eaither A or C but not sure

Answer 1

Using the Pythagorean Theorem, I found the distance to be 7.616 miles.

a^2 + b^2 = c^2
3^2 + 7^2 = c^2
9 + 49 = 58
square root of 58 = 7.616

Answer 2

simple case of using Pythagoras

d^2 = 3^2 + 7^2
d^2 = 58
d = √58 = 7.616

Answer 3

http://www.arcytech.org/java/pythagoras/history.html