A locker combination has three nonzero digits, with no repeated digits. If the first digit is a 2, what is the probability the second digit is also even?

3 answers

Think of the possibilities left. Since 2 is used the available even numbers are 4,6,and 8. The entire group of numbers that are still possible is 1,3,4,5,6,7,8,9. Representing the probability of an even is now simple.

this makes no sense

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