A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?

Answer 1

There are 9 possible digits, 4 of which are even and 5 are odd.
Digits cannot be repeated and 1st two are even, so that leaves the possibility of 2 even numbers and 5 odd numbers left.

You should be able to take it from here. :)

Answer 2

thanks for help