A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?

Answer 1

Assuming that the combination choices consist of single digits,
and we have only 4 even digits (2,4,6,8) where 2 are already used up,
we only have 2 out of 7 to pick from
so prob(your event) = 2/7

Answer 2

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