Solve this equation for X:
Initial kinetic energy = work done aqainst friction
(1/2) M*Vo^2 = M*g *Uk * X
M cancels out. Uk = 0.050
A loaded dogsled has a mass of 400kg and is being pulled across a horizontal, paced snow surface at a velocity of 4.0m/s (N). Suddenly, the harness separates from the sled. If the coefficient of kinetic friction for the sled on the snow is 0.0500, how far will the sled coast before stopping?
3 answers
4 m
This needs the kinematic equation - vf^2 = vi^2 + 2 x a x d
vf = 0 ( since he'll stop)
vi = 4.0
a = ( must be found)
d = ???? ( for now)
to find a
a is decelleration, because their is no applied force.
fnet = -uk x Ffk
m x a = -0.0500 x m x g
since there are m's cross them out.
a = -0.0500 x g
a = -0.49 m/s^2
fill in to the kinematic equation
vf^2 = vi ^2 + 2 x a x d
0 = 16 + 2 x -0.49 x d
d = -16.32
rounded (16m)
vf = 0 ( since he'll stop)
vi = 4.0
a = ( must be found)
d = ???? ( for now)
to find a
a is decelleration, because their is no applied force.
fnet = -uk x Ffk
m x a = -0.0500 x m x g
since there are m's cross them out.
a = -0.0500 x g
a = -0.49 m/s^2
fill in to the kinematic equation
vf^2 = vi ^2 + 2 x a x d
0 = 16 + 2 x -0.49 x d
d = -16.32
rounded (16m)