(i) if the velocity is constant there is no acceleration so the force up from the floor = weight down = m g = 80*9.8 Newtons
(i) If we accelerate UPWARDS at 2 m/s^2
then Fup-Fdown = m a
Fup - m g = m a
Fup = 80(9.8 + 2) Newtons
A load of mass 80kg is placed in a lift. Calculate the reaction between the floor of the lift and the load when the lift moves upwards:
(i) at constant velocity,
(ii) with an acceleration 2ms
2 [Take g 9.8ms 2].
4 answers
Ssdg2
Hey,I don't know the answer that's y I browsed it. Thanks for ur understanding
No problem, feel free to ask any question you have!