A little bumblebee accelerates uniformly at 1.5 m/s2 from rest to 22 m/s. Immediately upon reaching 22m/s, the brakes are applied and it stops 2.5 s later. Find the total distance traveled.

Answer 1

Phase 1
v = a t
22 = 1.5 t
t = 22/1.5
average speed = 11
so x = 11 *22/1.5

Phase 2
starts at x = 11*22/1.5 and t = 22/1.5
average speed during stop = 11 again
time to stop = 2.5
so stopping distance = 11 * 2.5
so
x = 11*22/1.5 + 11*2.5