A liquid spray of mass 384 g is packed in a cylindrical container of internal radius 3.2cm. Given that the density of the liquid is 0.6g/cm3, calculate to 2 decimal places the height of liquid in the container.

Answer 1

.6/1 = 384/x
x = 384/.6 = 640
the gas occupies 640 cm^3 in the can

volume of can = πr^2 h
π(3.2^2)h = 640
h = 640/(10.24π) = 19.89 cm

Answer 2

the volume of the liquid of height h is

v = πr^2*h
also,
v = (384g)/(0.6g/cm^3)

So, equate the two, plug in r, and solve for h.