a liquid cools in 6 minutes from 80degrees Celsius to 60degrees Celsius .what will it's temperature be after 10 minutes.temperature of the surrounding is 30degrees Celsius

Answer 1

Are you using Newton's cooling law?

T(t) = 30 + 50e^(-kt)

Now use the fact that
T(6)=60 to find k.

Then evaluate T(10)