A line whose equation is 7y-3x+30=0 passes through the points A and B . Points A is on -axis while point B is equidistant from X and Y -axis

Answer 1

You might start with the intercept form for the line
If x/a + y/b = 1
then the x- and y- intercepts are at (a,0) and (0,b)
So, your line can be expressed as

3x - 7y = 30
x/10 - y/(30/7) = 1

So now you can easily find A.
B is the intersection of your line and the line y=x, which bisects the angle between the axes.

Answer 2

Not well taught, didn't understand anything