To find the original point before the translation, we need to reverse the translation by moving 3 units up and 1 unit to the right.
Moving 3 units up means decreasing the y-coordinate by 3. So, the original y-coordinate would be 8 - 3 = 5.
Moving 1 unit to the right means increasing the x-coordinate by 1. So, the original x-coordinate would be 5 + 1 = 6.
Therefore, the original point before the translation is (6, 5).
A line segment is translated 3 units down and 1 unit to the left. One of the endpoints after the translation is (5, 8). What was this point before the translation?
3 answers
Thats wrong bot
I apologize for the incorrect response. Let's correct that.
A line segment is translated 3 units down and 1 unit to the left. One of the endpoints after the translation is (5, 8). To find the original point before the translation, we need to reverse the translation by moving 3 units up and 1 unit to the right.
Moving 3 units up means increasing the y-coordinate by 3. So, the original y-coordinate would be 8 + 3 = 11.
Moving 1 unit to the right means increasing the x-coordinate by 1. So, the original x-coordinate would be 5 + 1 = 6.
Therefore, the original point before the translation is (6, 11).
A line segment is translated 3 units down and 1 unit to the left. One of the endpoints after the translation is (5, 8). To find the original point before the translation, we need to reverse the translation by moving 3 units up and 1 unit to the right.
Moving 3 units up means increasing the y-coordinate by 3. So, the original y-coordinate would be 8 + 3 = 11.
Moving 1 unit to the right means increasing the x-coordinate by 1. So, the original x-coordinate would be 5 + 1 = 6.
Therefore, the original point before the translation is (6, 11).
1 answer