The slope of this line is
\[\frac{7 - 2}{1 - (-8)} = \frac{5}{9}.\]The line passes through $(1,7),$ so the equation of the line is
\[(y - 7) = \frac{5}{9} (x - 1).\]Multiplying both sides by 9, we get
\[9y - 63 = 5x - 5.\]Thus, the equation is $5x - 9y = 58,$ so $A = \boxed{5},$ $B = -9,$ and $C = 58.$
A line passes through the points $P$ and $Q.$ If $P = (-8,2)$ and $Q = (1,7),$ then write the equation of this line in the form $Ax + By = C,$ where $A$, $B$, and $C$ are integers with greatest common divisor $1,$ and $A$ is positive.
1 answer